thx. tama. meanwhile you can make the following choice of changes:
from
for ($x = 0; $x <= count($PBArray)-1; $x++) {
echo $x;
I prefer option c , but you might like option A
a) for ($x = 0; $x <= count($PBArray)-1; $x++) {
b) for ($x = 0; $x <= count($PBArray)-1; $x++) {
// echo $x;
c) for ($x = 0; $x <= count($PBArray)-1; $x++) {
echo $peregrine_is_on_vacation;
d) // leave it as is and enjoy the numbers.
I may not provide the completed solution you might desire, but I do try to provide honest suggestions to help you solve your issue.
Comments
Noticed that too - thanks @tama
thx. tama. meanwhile you can make the following choice of changes:
from
for ($x = 0; $x <= count($PBArray)-1; $x++) { echo $x; I prefer option c , but you might like option A a) for ($x = 0; $x <= count($PBArray)-1; $x++) { b) for ($x = 0; $x <= count($PBArray)-1; $x++) { // echo $x; c) for ($x = 0; $x <= count($PBArray)-1; $x++) { echo $peregrine_is_on_vacation; d) // leave it as is and enjoy the numbers.I may not provide the completed solution you might desire, but I do try to provide honest suggestions to help you solve your issue.